Question 998619
n, number of cans of soup


One store: {{{10*(1/8)*n}}}, although the store might not allow this way in practice.


Second store: {{{6*(1/5)*n+3}}}


Those are the cost formulas, and you could assume the prices given were just a grouping for efficiency of stating the prices.


For what number of cans, n, will the costs at both stores be equal.
{{{10(1/8)n=6(1/5)n+3}}}
-
{{{(5/4)n=(6/5)n+3}}}
{{{(5/4-6/5)n=3}}}
{{{(25/20-24/20)n=3}}}
{{{(1/20)n=3}}}
{{{highlight(n=60)}}}


Sixty cans at each place.