Question 998561
Call the smaller one x.  The larger must be x + 2.
Now we can write
x(x+2)-10=5x+3(x+2)
Now we solve this...
x^2+2x-10=5x+3x+6 = 8x + 6
Combining like terms we get
x^2-6x-16=0
Factoring we get
(x-8)(x+2)=0
x = 8 and x = -2
Thus
x+2 = 10 and x+2 = 0