Question 998318
Equal but opposite in sign.
{{{f(x)=(x-a)(x+a)=x^2-ax+ax-a^2=x^2-a^2}}}
So there can be no {{{x}}} term.
{{{2x^2+4x-17=4x}}}
{{{2x^2-17=0}}}
{{{2x^2=17}}}
{{{x^2=17/2}}}
{{{x=0 +- sqrt(17/2)}}}
.
.
.
{{{s=-16t^2+184t=529}}}
{{{-16t^2+184t=529}}}
Complete the square,
{{{-16(t^2-(23/2)t)=529}}}
{{{-16(t^2-(23/2)t+(23/4)^2)=529-16(23/4)^2}}}
{{{-16(t-23/4)^2=529-529}}}
{{{-16(t-23/4)^2=0}}}
{{{t-23/4=0}}}
{{{t=23/4}}}