Question 998447
Point-slope form comes from the definition for slope of a line.
If two points  (x,y) and (p,v) the number, m, for slope is {{{m=(y-v)/(x-p)}}}.
{{{m(x-p)=((y-v)/(x-p))(x-p)}}}
{{{m(x-p)=y-v}}}
{{{highlight_green(y-v=m(x-p))}}}------the point-slope form for a line.


Use your given values and just substitute.  That's it!
{{{y-4=-6(x-(-1))}}}
and you might want the simple simplification,
{{{highlight_green(y-4=-6(x+1))}}}.


Change from the point-slope form into the slope-intercept form:  SIMPLE algebra.
If starting in general with  {{{y-v=m(x-p)}}}
(But watch your signs very carefullly);
{{{y=m(x-p)+v}}}
{{{y=mx-mp+v}}}
and then either as {{{highlight(y=mx-(mp-v))}}}   or  {{{highlight(y=mx+(v-mp))}}}.