Question 85438
Question:


-3(6y-4)-y=-4(y-3)


Answer:

Check your question once again....



If the stated question is  correct, the solution is....

-3 ( 6y - 4 )- y = -4( y - 3 )



Remove the parenthesis as by multiplying the terms....



-3 * 6y -3 * -4 - y = -4 * y - 4 * -3



==> -18y  + 12 - y = -4y + 12



==> -18y - y + 12 = -4y + 12



==> -19y + 12  = -4y + 12




==> add 4y on both sides of the expression......



==> -19y + 4y + 12 = -4y + 4y + 12



==> -15y + 12  = 12



Subtract 12 from both sides...


==> -15y = 0



==> y = 0



Hoe you found the explanation useful....



Regards.



Praseena..