Question 998450
log(x)+log(x-15)=2


Assumed base ten:
{{{log((x))+log((x-15))=2}}}


Rule of Logarithms says do this.
{{{log((x(x-15)))=2}}}


Put into exponential form:
{{{10^2=x(x-15)}}}



Simpler algebra from there.
{{{x^2-15x-100=0}}}
{{{(x-10)(x+5)=0}}}
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Either x=10  or x=-5.


Review laws of exponents and rules of logarithms.