Question 998368
 For f(x)= 1/x-5 and g(x)= x^2+2, 
find: 
a. (f o g)(x) = f[g(x)] = f[x^2+2] = 1/[x^2+2-5] = 1/[x^2-3]
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b. (g o f)(6) = g[f(6)] = g[1/(6-5)] = g[1] = 1^2+2 = 3
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Cheers,
Stan H.
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