<PRE><B>Question 998337</B>
Given 5x+2y-6=0 write equation of a line that is perpendicular going through point (0,-3).
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Slope of the given line::
y = (-5/2)x + 3
slope = -5/2
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Slope of the perpendicular line:: 2/5
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Form of the answer::
y = mx + b
y = (2/5)x -3
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Cheers,
Stan H.
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