Question 998302
Please help me understand how to solve this problem, specifically what to do with the fraction..
1/7(log base 6 (x)+3log base 6 (y))

I can understand that it becomes log base 6 (xy^3), but do I distribute the 1/7 or change it to the 7th square root?
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{{{log(6,xy^3)}}} is 1 term, no distributing.
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{{{log(6,xy^3)/7 = log(6,root(7,xy^3))}}}