Question 998294
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Instead of doing your problem for you, I will instead do
one just exactly in every detail step-by-step like yours:
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What is the 38th term of the sequence: -35, -31, -27, -23
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2nd term - 1st term = (-31)-(-35) = -31+35 = 4
3rd term - 2nd term = (-27)-(-31) = -27+31 = 4
4th term - 3rd term = (-23)-(-27) = -23+27 = 4
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Since those are all the same the sequence is arithmetic
with common difference d = 4 and first term a<sub>1</sub> = -35,
and number of term n = 38

So substitute a<sub>1</sub> = -35, n = 38, and d = 4 in

a<sub>n</sub> = a<sub>1</sub> + (n-1)d
a<sub>30</sub> = -35 + (38-1)4
a<sub>30</sub> = -35 + (37)4
a<sub>30</sub> = -35 + 148
a<sub>30</sub> = 113

No do yours exactly the same way, step by step.

Edwin</pre>