Question 998270
c cows, p pigs
{{{system(c+p=12,p<c,900c+700p<=9800)}}}


{{{9c+7p<=98}}}
-
{{{c=12-p}}}
substitute
{{{9(12-p)+7p<=98}}}
{{{108-9p+7p<=98}}}
{{{108-2p<=98}}}
{{{108-98<=2p}}}
{{{10<=2p}}}
{{{highlight(p>=5)}}}
-
{{{p=12-c}}}
substitute
{{{9c+7(12-c)<=98}}}
{{{9c+84-7c<=98}}}
{{{2c<=98-84}}}
{{{highlight(c<=7)}}}


One of the requirements was fewer pigs than cows.  This is  {{{highlight_green(p<c)}}}.  This means that:  c=7,p=5; as a possibility.

In fact, the only possible answer here.  


Last question:  Bucthcer's profit will be based on just the one data point, {{{c*550+p*325}}}
{{{7*550+5*325}}}
{{{highlight(5475)}}}