Question 998237
Standard Form  (but which direction?), {{{y=a(x-h)^2+k}}}.


Vertex is given.
{{{y=a(x-2)^2+5}}}


A point on graph is included.   Solve for factor a.
{{{y-5=a(x-2)^2}}}
{{{a=(y-5)/(x-2)^2}}}
{{{a=(2-5)/(-5-2)^2}}}
{{{a=-3/49}}}


ANSWER:   {{{highlight(y=-(3/49)(x-2)^2+5)}}}