Question 998217
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If an 85 average is needed, then the total number of points scored must be 85 times the total number of tests, 5 in this case.  The required score to achieve the 85 average is 85 times 5 minus the sum of the scores already achieved.  In this case, you can't get there from here.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it

*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \  

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