Question 998208
If a fisherman has a {{{0.02}}} probability of catching a fish on any day he goes out fishing,
that fisherman has a {{{1.00-0.02=0.98}}} probability of not catching amy fish on any day he goes out fishing.
Those would be the fisherman's probability of catching a fish and coming home empty handed each day.
The probability for one day is independent of the probability for another day.
If we consider {{{6}}} consecutive days (and even if we considered any 6 random days),
the probability that the fisherman will come home empty handed each one of those {{{6}}} days is
{{{0.98*0.98*0.98*0.98*0.98*0.98=0.98^6=about0.89}}}(rounded).