Question 997977
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Since I can create a figure such that line segments AB and DE are indeed perpendicular, but angle ABD is NOT congruent to angle CBD, your assertion is not generally true and therefore cannot be proven.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it

*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \  

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