Question 997994
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Let *[tex \Large r] represent Pierre's rate.  Then Charles' rate is *[tex \Large 3r].  Distance equals rate times time, so:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 3rt\ =\ 45]


and


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ r(t\ +\ 3)\ =\ 45]


Solve the 2X2 system of equations for *[tex \Large r]


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it

*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \