Question 997891
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*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{-6\ +\ 18i}{2}\ =\ -3\ +\ 9i]


The other root is


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ -3\ -\ 9i]


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it

*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \