Question 997863
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*[tex \LARGE \ \ \ \ \ \ \ \ \ \ P\ =\ 2l\ +\ 10]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ A\ =\ 5l]


So


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 5l\ >\ 2l\ +\ 10]


Solve for *[tex \Large l]


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it

*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \