Question 997829
<font face="Times New Roman" size="+2">


If you have a local extremum on the interval, then there will be a point in the interval where the first derivative is equal to zero, which is to say:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 4x\ -\ 9\ =\ 0]


Hint:  It is NOT 4/9.


If the second derivative is positive at that point, then the extremum is a minimum, if the second derivative is negative, the extremum is a maximum.


As for the endpoints of the interval, you need to find the value of the function at each of the endpoints and compare those function values to the function values at your other critical points.  Basically, you have three critical points, one of which is a minimum, one of which is a maximum, and the other is somewhere in between.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it

*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \