Question 997680

Can you please help me with this question? Write an equation for the line that passes through (5, -4) and is perpendicular to the graph of 5x-2y=-6. this is my work so far:

2y=5x+6 then y=5/2 x + 3

I can't figure out how to find the perpendicular equation. Can you please help me with this part?

Thanks!
<pre>Your equation is correct! Good job!!
The equation that's perpendicular to {{{y = (5/2)x + 3}}} will have a slope, or m of: {{{- 2/5}}}
Using the slope, or {{{m = - 2/5}}}, the point: (5, - 4), and the point-slope form: {{{y - y[1] = m(x - x[1])}}}, we get: 
{{{y - - 4 = -(2/5)(x - 5)}}} 
{{{y + 4 = - (2/5)x + 2}}}
{{{y = - (2/5)x + 2 - 4}}}
Perpendicular equation is then: {{{highlight_green(y = -(2/5)x - 2)}}}, or {{{highlight_green(2x + 5y = - 10)}}}