Question 997627
The equation written correctly, or in more precise manner is  {{{x-1=-(1/12)y^2}}}.
This is a parabola with symmetry axis parallel to the x-axis, and graph of parabola opens to the left, as indicated by coefficient  NEGATIVE  1/12.  This coefficient  {{{-1/12}}} tells you information about how far is focus and directrix from the vertex.  YOUR equation's vertex is  (1,0).


Learn better how this works through these two videos:


<a href="https://www.youtube.com/watch?v=M8LGsQMwwj4">Derive equation for parabola from focus and directrix</a>


<a href="https://www.youtube.com/watch?v=Wworlx39KfQ">Equation for parabola from directrix and focus but vertex is NOT at the Origin</a>


According to the form of the equation used in the derivations,  {{{4p=(1/12)}}}, and |p| is how far vertex is from either focus or directrix.
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{{{p=(1/4)(1/12)}}}
{{{p=1/48}}}


Focus is on the concave side, to left of the vertex.
{{{x=1-1/48}}}
{{{x=48/48-1/48}}}
{{{x=47/48}}} and {{{y=0}}}, this y-value unchanged.
FOCUS:   ( 47/48, 0 )


Directrix would be on the other side and is the vertical line {{{x=1&1/48}}}.