Question 997434
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Kevin and Randy have a jar containing 82 coins, all of which are either quarters or nickles. The total value of the coins in the jar is 13.30. How many of each type of coin do they have?
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You can solve this problem even without using equations.


Let us suppose for a moment that all  34  coins are  10-cent. 

Then their value is  82*10 = $8.20.  It is less than  $13.30 in &nbsp $5.10 = 510 cents. 

It is clear that the difference is due to presence of  25-cent coins that we intently counted as  10-cent coins.

It is also clear that the number of these  25-cent coins is  {{{510/(25-10)}}} = {{{510/15}}} = 34  to compensate the difference. 

So, the answer is:  there are  34  of  25-cent coins and  82-34 = 48  of  10-cent coins.


The solution is completed.


If you want to see more problems solved in this way,  look into these lessons 

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&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=http://www.algebra.com/algebra/homework/word/misc/Problem-on-animals-at-a-farm.lesson>Problem on animals at a farm</A> &nbsp;and 

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=http://www.algebra.com/algebra/homework/word/misc/Problem-on-tablets-in-containers.lesson>Problem on pills in containers</A> 

in this site.