Question 997418
The Perimeter of a rectangle is 54m.
2L + 2W = 54
simplify, divide by 2
L + W = 27
L = (27-W); use this form for substitution
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 If the width is doubled and the length were increased by 15m, the perimeter would be 98m.
2(L+15) + 2(2W) = 98
simplify, divide by 2
 (L+15) + 2W = 49
L + 15 + 2W = 49
Substitute (27-W) for L
(27-W) + 15 + 2W = 49
W + 42 = 49
W = 49 - 42
W = 7 m is the width
then
L = 27 - 7
L = 20 m is the length
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Check this by finding the perimeter with these value
2(20) + 2(7) =
40 + 14 = 54
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 What are the length and width of the rectangle? 20 by 7