Question 997234
A guess that you mean to start with {{{log(10,(x-4))+log(10,(x+4))=3}}}


{{{log(10,((x-4)(x+4)))=3}}}
{{{log(10,(x^2-16))=3}}}
{{{10^3=x^2-16}}}
{{{x^2=10^3+16}}}
{{{x^2=1000+16}}}
{{{x^2=1016}}}
{{{x^2=2*508=2*2*254=2*2*2*127}}}, best stated as {{{x^2=2*2*254}}} because the 127 is a prime number.
{{{(x^2)^(1/2)=(2*2*254)^(1/2)}}}
{{{x=2*254^(1/2)}}}  or  {{{x=2*sqrt(254)}}}