Question 997159
{{{(16xy^2)/(10x^3y)}}}



{{{(16/10)*((x)/(x^3))*((y^2)/(y))}}}



{{{(8/5)*(x^(1-3))*(y^(2-1))}}}



{{{(8/5)*(x^(-2))*(y^(1))}}}



{{{(8/5)*1/(x^2))*(y)}}}



{{{(8y)/(5x^2)}}}



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So {{{(16xy^2)/(10x^3y)}}} simplifies to {{{(8y)/(5x^2)}}}