Question 997131
Solution A is 10% sugar while solution B is 30% sugar. A student wants to have a 50 liter of solutions A and B that is 18% sugar. How many liters of each solution should be used?
----------------------------------------------------------------------


{{{(0.1*x +0.3*(50-x))/50}}} = 0.18.


Numerator is the amount of the soluted sugar, x is a volume of the 10% solution.


0.1x + 0.3*(50-x) = 0.18*50,


0.1x - 0.3x = 9 - 15,


-0.2x = -6,


x = {{{6/0.2}}} = 30.


<B>Answer</B>. 30 liters of 10% solution and 50-30 = 20 liters of 30% solution.