Question 85325
Since the problem states that the baseball is initially shot upward from ground level, you
know that s0 = 0.
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In that case the equation is reduced to:
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s = -16t2 + v0t
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The problem also tells you that the initial velocity is +32 ft/sec (the + means that it is
in the upward direction). Substitute this and the equation becomes:
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s = -16t^2 + 32t
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You are asked how high the ball is after 1 second. The units that apply in this equation are 
feet and seconds. Substitute 1 for t and this will determine s in feet.
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s = -16(1)^2 + 32(1) = -16 + 32 = 16 ft
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The ball will be 16 feet high when the time after launch is 1 second.
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Hope this helps you to understand the problem.