<PRE><B>Question 85325</B>
Suppose a baseball is shot up from the ground straight up with an initial velocity of 32 feet per second. A function can be created by expressing distance above the ground, s, as a function of time, t. This function is s = -16t2 + v0t + s0 
• 16 represents ½g, the gravitational pull due to gravity (measured in feet per second^2). 
• v0 is the initial velocity (how hard do you throw the object, measured in feet per second).
• s0 is the initial distance above ground (in feet). If you are standing on the ground, then s0 = 0.
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s(t) = -16t^2+32t+0
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How high will the ball be above ground after 1 second?
s(1) = -16(1^2) + 32(1)
s(1) = -16 + 32
s(1) = 16 ft.
The height will be 16 ft after 1 second.
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Cheers
Stan H.
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