Question 997004
I have a question here and I don't know where to start. Can you help me?

{{{sqrt(x-1)+2=sqrt(2x+5)}}}
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That's not a question, it's an equation.
If you want to solve for x:
{{{sqrt(x-1)+2=sqrt(2x+5)}}}
Square both sides.
{{{x-1 + 4sqrt(x-1) + 4 = 2x+5}}}
{{{4sqrt(x-1) = x+2}}}
Square again
{{{16(x-1) = x^2 + 4x + 4}}}
{{{x^2 - 12x + 20 = 0}}}
(x-2)*(x-10) = 0
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Check for extraneous values.