Question 85332
<pre>{{{-6(x+3)-10=3(-2x-5)-13}}}Distribute
{{{-6x-18-10=-6x-15-13}}}add 28 to both sides
{{{-x=-x}}}Divide by negative one
{{{x=x}}}

This means that for this particular equation, x can be ANY value.
The domain is (-infinity, infinity)
Any X value will satisfy the equation above ^_^

For example, x can equal (any number, even) one:
-6(<b>1</b>+3)-10=3(-2<b>(1)</b>-5)-13
-6(4)-10=3(-7)-13
-24-10=-21-13
-34=-34  Thus the equation is satisfied.

Another example:  X=0 (note please that <i>all</i> values of x will satisfy this equation)
-6(<b>0</b>+3)-10=3(-2<b>(0)</b>-5)-13
-6(3)-10=3(-5)-13
-28=-28
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