Question 996887
ball is 6 times the radius =19.8cm
 diameter 6.6 cm

so three balls can be fytted into the can

Empty space in the can = Volume of can - volume of 3 balls

Vol of can height = 19.8
radius = 3.3cm

v= pi r^2 h

V= 3.14 * 3.3^2 * 19.8 = 677.05 cm^3

Volume of spheres = 4/3 * pi * r^3

= (4/3) * 3.14 * (3.3)^3 = 150.45 cm^3

Volume of 3 balls = 3* 150.45 = 451.36

difference of volumes = empty space