Question 996768
Find the second derivative of the function
 f(x) = (6x – x2)^10
f'(x) = 10*(6x - x^2)^9*(6 - 2x)
f'(x) = 60*(6x - x^2)^9 - 2x*(6x - x^2)^9
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f"(x) = 9*60*(6x - x^2)^8*(6-2x) -2*(6x - x^2)^9 - 2x*9*(6x - x^2)^8*(6-2x)
= {{{540*(6-2x)*(6x - x^2)^8 -2(6x - x^2)^9 -18x*(6-2x)*(6x - x^2)^8}}}
= {{{(36x^2 - 216x + 3240)*(6x - x^2)^8 - 2(6x - x^2)^9}}}
= {{{(36x^2 - 216x + 3240)*(6x - x^2)^8 - (12x - 2x^2)*(6x - x^2)^8}}}
= {{{(38x^2 - 228x + 3240)*(6x - x^2)^8}}}