<PRE><B>Question 996735</B>
 The sum of three digits of a number is 14. The number is 14 larger than twenty times the tens digit. The sum of the tens digit and the unit digit is 12 larger than the hundreds digit. Find the number. 
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Let the number be 100a+10b+c
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Equations:
a + b + c = 14
100a + 10b + c = 20b+14
b + c = a+12
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Rearrange:
a + b + c = 14
100a - 10b + c = 14
-a + b + c = 12
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Solve the system by any Method to get:
a = 1
b = 9
c = 4
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Ans: Number is 194
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Cheers,
Stan H.
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