Question 996731
One number is four more than the other. The square of the smaller number increased by three times the larger is 66. Find the two numbers. 
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Equations:
x = y + 4
Note:: That means "y" is the smaller number
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y^2 + 3x = 66
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Substitute for "x" and solve for "y"::
y^2 + 3(y+4) - 66 = 0
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y^2 + 3y - 54 = 0
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(y-6)(y+9) = 0
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y = 6 or y = -9
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If y = 6, x = y+4 = 10
If y = -9, x = y+4 = -5
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Cheers,
Stan H.
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