Question 85309
There's a thing called the 'constant of variation'
Write the relation like this:
{{{y = k(1/x)}}} This says "Y varies inversely with x with k being the
constant of variation
{{{-5 = k(1/12.5)}}} Now find k
{{{k = (-5)(12.5)}}}
{{{k = - 62.5}}}
Now finish the problem
{{{15 = k(1/x)}}}
{{{15 = (-62.5)(1/x)}}}
{{{x = -(62.5/15)}}}
{{{x = -4.167}}}