Question 996632
According to a study conducted by a statistical organization, the proportion of Americans who are satisfied with the way things are going in their lives is 0.76. Suppose a random sample of 105 Americans is obtained. Part C says what is the probability that 77 or fewer Americans in the sample are satisfied with their lives? 
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Binomial Problem with n = 105 and p(satisfied) = 0.76
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P(0<= x <=77) = binomcdf(105,0.76,77) = 0.2947
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Cheers,
Stan H.
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