Question 996489
Let's call one number x and another number y.
one number is 11 more than another number:
x = y+11 <---Value of x
three times the larger number exceed four times the smaller number by 4?
3x+4 = 4y Now, in this equation, let's replace x with the value of x:
3(y+11)+4= 4y Multiply on left
3y+33+4= 4y Add numbers on left and subtract 3y on both sides
37= 1y  and we can write this simply as
y= 37
Proof
One number is 11 more than another number, and since 37 is "another number", 37+11= "one number", 37+11= 48 Next, the problem says, three times the larger number exceed four times the smaller number by 4:
4*37-3*48= 4 Multiply
148-144= 4 We've got the right answer