Question 996277

An 112 ounces mixture is created by combining two ethylene solutions. One solution is 10% ethylene and the other is 2% ethylene. If the final mixture is comprised of a 7.9% ethylene solution, then how much of the 10% solution was used?
<pre>Let amount of 10% ethylene be T
Then amount of 2% ethylene = 112 – T
We then get: .1T + .02(112 – T) = .079(112)
.1T + 2.24 - .02T = 8.848
.1T - .02T = 8.848 – 2.24
.08T = 6.608
T, or amount of 10% ethylene = {{{6.608/.08}}}, or {{{highlight_green(82.6)}}} oz