Question 996404
your equation is:


e^(x^2) = e^(13x) * 1/e^40


this is equivalent to:


e^(x^2) = e^(13x) * e^(-40)


this is equivalent to:


e^(x^2) = e^(13x - 40)


this is true if and only if x^2 = 13x - 40


subtract 13x from both sides of this equation and add 40 to both sides of this equation to get:


x^2 - 13x + 40 = 0


factor this equation to get:


(x-8) * (x-5) = 0


set each of these factors equal to 0 and solve for x to get:


x = 8 or x = 5.


those are your solutions.