Question 996339

 {{{h(f(g(x)))= h(f(2/x))}}}......since {{{f(g(x))=f(2/x)=(2/x)^2/2=(4/x^2)/2=4/2x^2=2/x^2}}} we have

 {{{h(f(g(x)))= h(2/x^2)}}}....given {{{h(x)=4x-3}}}, substitute {{{x}}} with {{{(2/x^2)}}}

 {{{h(f(g(x)))= 4(2/x^2)-3}}}

{{{h(f(g(x)))= 8/x^2-3}}}

{{{h(f(g(x)))= 8/x^2-3x^2/x^2}}}

{{{h(f(g(x)))= (8-3x^2)/x^2}}}

so, your answer is C