Question 996349
what is the square root of 8x divided by the cubed [sic] root of 16 x squared 
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It's ambiguous.
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If it's {{{sqrt(8x)/root(3,16x^2)}}}
= {{{root(6,(8x)^3)/root(6,(16x^2)^2)}}}
= {{{root(6,(8x)^3/(16x^2)^2)}}}
= {{{root(6,512x^3/(256x^4))}}}
= {{{root(6,2/x)}}}
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= {{{root(6,2x^5)/x}}}