Question 996272
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Let us do it together.


1.) The solution to  {{{sqrt(2x+3)}}} - {{{sqrt(x-1)}}} = {{{1}}} is x=3?  true or false?     Substitute   x=3  into this equation and check if the right side is equal to the left.  It is easy.


2.) The solution to the radical function  {{{1}}} = {{{sqrt(x-5)}}}  is x=6?  true or false?     Substitute x=6 into equation and check.  It is easy.


3.) Solve: {{{sqrt(x)}}} = {{{sqrt(2x-6)}}}.     Square both sides.  It is easy.


4.) Solve: {{{3}}} + {{{sqrt(x-3)}}} = {{{6}}}.     Move  3  to the right side with the opposite sign.  Calculate.  Then square both sides.


5.) Solve: {{{sqrt(x-3)}}} = {{{sqrt(2)}}} - {{{sqrt(x)}}} for x.     Not sure that I correctly put parentheses.  IT IS YOURS RESPONSIBILITY.