Question 996252
For x^2+12=0, the a=1, b=0, and c=12.
Thus, from the quadratic formula,
x = [-0 +- SQRT(0^2 - 4(1)12)] / 2
x = +- SQRT(-48) / 2
x = +- 4i*SQRT(3) / 2
x = +- 2i*SQRT(3)