Question 85268
Pat is 20 years older than his son Patrick. In two years Pat will be twice as old as Patrick. How old are they now?
What I have so far is: Patrick's current age is X, Pat's Current age is X+20. In two years Patrick's age will be X+2 and Patrick's age will be X+20+2.
So I tried X+2(Pat's future age)plus x+20+2(Patrick's future age) = 2X(Pat being twice the age of Patrick). Or X+2+X+20+2=2X which reduces to 2X+24=2X which gives 2X-2X=-24, or 0=-24. Which is not the right answer.
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NOW DATA:
Patrick is x; Pat =x+20
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2 YEARS FROM NOW DATA:
Patrick will be x+2; Pat will be x+22

EQUATION:
x+22 = 2(x+2)
x+22 = 2x+4
x=18 (Patrick's age now)
x+20 = 38 (Pat's age now)
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Cheers,
Stan H.