Question 996133
{{{3x-2*0+6=0}}}
{{{3x=-6}}}
{{{x=-2}}}
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Point (-2,0).


{{{x+3y+1=0}}}
change to 
{{{x+3y+c=0}}}
{{{c=-x-3y}}}
{{{c=-(-2)-3(0)}}}
{{{c=2}}}
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Resulting equation found, {{{x+3y+2=0}}}.
This may not be what you really want.  The problem description is lacking.  This found line is PARALLEL to the first equation mentioned in your description and passes through the intercept of your second equation of your description.