Question 996063
You also need to solve {{{3-x>=0}}} to get {{{x<=3}}}


So {{{x<>3}}}, {{{x<>5}}}, and {{{x<>-1}}} to avoid dividing by zero. In addition,  {{{x<=3}}} to make sure the stuff under the square root isn't negative.


Put this all together to get this final answer in interval notation
*[Tex \LARGE (-\infty, -1)\cup(-1,3)]


Note: you basically start with {{{x<=3}}} and convert to interval notation. You don't need to worry about x = 5 because that's not even in the interval. Then you just pull out x = -1 to get that final answer above.