Question 996038
A simple random sample size n=350 individuals who are currently employed is asked if they work at home at least once per week. Of the 350 employed individuals surveyed, 35 responded that they did work at home at least once per week. Construct 99% confidence interval for the population of employed individuals who work at home at least once per week. What is lower and upper bound round 3 decimal places as needed.
============
Sample proportion:: 35/350 = 1/10 = 0.10
ME: = 2.5758*sqrt[0.1*0.9/350] = 0.041 
------
99% CI:: 0.100-0.041 < p < 0.100+0.041
-------------
Cheers,
Stan H.
----------