Question 85272
note: I'm going to start out with y


{{{3(y-2)^2-3(y-2)-6}}}


Let {{{x=y-2}}}


{{{3x^2-3x-6}}}

Now factor


*[invoke change_this_name4450 3, -3, -6]


Now replace x with {{{y-2}}} to get


{{{(3(y-2)-6)((y-2)+1)}}}


{{{(3y-6-6)(y-2-1)}}}Distribute


{{{(3y-12)(y-1)}}} Combine like terms


{{{3(y-4)(y-1)}}}Factor out the GCF of the first group


So our answer looks exactly like answer D (just replace y with x) 


So our answer is {{{3(x-4)(x-1)}}}