<PRE><B>Question 995974</B>
 Hi I need to graph the following quadratic equations:

y=x^2+2x+5
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The low point where x = -b/(2a) = -2/(2) = -1
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f(-1) = 1-2+5 = 4 giving you the low point (-1,4)
f(0) = 0+0+5 = 5 giving you the point (0,5)
f(-2) is symetric so have the point (-2,5)
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Plot those points and draw a parabola thru them::
{{{graph(400,400,-10,10,-10,10,x^2+2x+5)}}}
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Cheers,
Stan H.
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