Question 995804
Let f(x) = 2x^2 − 9x
Then f'(x) = 4x-9
And f"(x) = 4
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Find all extreme values (if any) of f on the interval [0, 9]. Determine at which numbers in the interval these values occur. NOTE: If there is no maximum value (or minimum value), then enter DNE in the corresponding blanks.
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Solve 4x-9 = 0
x = 9/4
Since f"(9/4) = 4 > 0, 
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Maximum Value: DNE 
Minimum Value: f(9/4) occurs at x = 9/4
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Cheers,
Stan H.
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